r^(2/5)-5r^(5/2)=0

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Solution for r^(2/5)-5r^(5/2)=0 equation: 


D( r )

r < 0

r < 0

r in <0:+oo)

r^(2/5)-(5*r^(5/2)) = 0

r^(2/5)-5*r^(5/2) = 0

r^(2/5)-5*r^(5/2) = 0

r^(2/5)*(1-5*r^(21/10)) = 0

-5*r^(21/10) = -1 // : -5

r^(21/10) = 1/5

r^(21/10) = 1/5 // ^ 10

r^21 = 1/9765625 // ^ 1/21

r = (1/9765625)^(1/21)

r^(2/5) = 0

1*r^(2/5) = 0 // : 1

r^(2/5) = 0

r = 0

r in { (1/9765625)^(1/21), 0 }

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